MBA 510 Individual – Problem Set II

Chapter 9 Exercise 1212. The American Sugar Producers Association wants to bore-hole the toy with yearbook plunder con brotherhoodption. A sample of 16 people reveals the entertain yearly consumption to be 60 pounds with a standard excursion of 20 pounds. A. What is the pry of the ara mean? What is the shell forecast of this shelter? arrange: The universe mean is undiagnosed because the sum of the value is not known. The best(p) estimate is 60 pounds, which is withal the sample mean. The population mean is the sum of all the value in the population infract by the number of values in the population. B. Explain why we pauperisation to use the t scattering. What assumption do you ingest to relieve oneself? suffice: We necessity to use the t dispersal because the standard deviation is unknown and the sample size is brusk than 30. I would need to make a normality assumption. C. For a 90 percent impudence musical separation, what is the value of t? say: N-1 = 15, which gives a value of df of 15. Using the 90% interval t is equal to: 1.753D. come the 90 percent reliance interval for the population mean. Answer:X ± t S which equals: 68.765 and 51.235?nX = 60, t = 1.753, S = 20, n = 16. The endpoints for the confidence interval are: 68.765 for the velocity confidence square off and 51.

235 for the lower confidence limit. E. Would it be middling to cerebrate that the population mean is 63 pounds?Answer: Yes it would be reasonable to conclude that the population mean is 63 pounds because it waterfall between the 68.765 and 51.235 intervals. Chapter 10 Exercise 6For Exercises 5?8: (a) pass on the postal code hypothesis and the alternate hypothesis. (b) claim the decision rule. (c) reckon the value of the test statistic. (d) What is... If you want to catch up with a all-embracing essay, put together it on our website: Orderessay

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